w^2-2950=0

Solution for w^2-2950=0 equation:

w^2-2950=0

a = 1; b = 0; c = -2950;
Δ = b2-4ac
Δ = 02-4·1·(-2950)
Δ = 11800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11800}=\sqrt{100*118}=\sqrt{100}*\sqrt{118}=10\sqrt{118}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{118}}{2*1}=\frac{0-10\sqrt{118}}{2}
=-\frac{10\sqrt{118}}{2}
=-5\sqrt{118}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{118}}{2*1}=\frac{0+10\sqrt{118}}{2}
=\frac{10\sqrt{118}}{2}
=5\sqrt{118}
$